Correct option is 2It is possible to have |C|<|A| and |C|<|B|

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Let $C = A + B$

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|C| is always greater than |A|

It is possible to have |C|<|A| and |C|<|B|

C is always equal to A+B

C is never equal to A+B

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detailed solution

Correct option is B

|C|=|A+B|≤|A|+|B|Hence it can be said thatThus, the statement |C|<|A| and |C|<|B| is correct.

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Let C=A+B

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Let $C = A + B$