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Let current i = 2 A be flowing in each part of a wire frame as shown in figure. The frame is a combination of two equilateral triangles ACD and CDE of side 1 m. It is placed in uniform magnetic field B = 4T acting perpendicular to the plane of frame.The magnitude of magnetic force acting on the frame is

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24N

zero

16N

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detailed solution

Correct option is A

FCAD=FCD=FCED ∴ Net force on the frame =3FCD=3Bil =(3)(2)(1)(4)=24 N (F=ilB)

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