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Q.

Let current i = 2 A be flowing in each part of a wire frame as shown in figure. The frame is a combination of two equilateral triangles ACD and CDE of side 1 m. It is placed in uniform magnetic field B = 4T acting perpendicular to the plane of frame.The magnitude of magnetic force acting on the frame is

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a

24N

b

zero

c

16N

d

8N

answer is A.

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Detailed Solution

FCAD=FCD=FCED ∴  Net force on the frame =3FCD=3Bil =(3)(2)(1)(4)=24 N (F=ilB)
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