Questions
Let denote the dimensional formula of the permittivity of the vacuum and that of the permeability of the vacuum. If = mass, =length,= time and = electric current, then
detailed solution
Correct option is B
F=14πε0·q1q2r2 ϵ0=q1q2[F]r2=[1T]2MLT-2L2=M-1 L-3 T4I2Speed of light,c=1ε0μ0 ∴μ0=1ε0[c]2=1M-1L-3T4I2LT-12=MLT-2I-2Talk to our academic expert!
Similar Questions
The pairs of physical quantities that have not the same dimensions is (are)
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