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Let g be the acceleration due to gravity at the earth's surface and K be the rotational kinetic energy of the earth. Suppose the earth's radius decreases by . Keeping mass of earth and angular momentum constant, then
detailed solution
Correct option is B
g=GMR2g∝R-2change in g=(-2)(% change in R)=(-2)(-2)=+4%Rotational kinetic energy,K=L22IL= angular momentum = constant I=25mR2K∝R-2% change in K=(-2)(% change in R)=(-2)(-2)=+4%Talk to our academic expert!
Similar Questions
A uniform ring of mass M and radius r is placed directly above a uniform sphere of mass 8 M and of same radius R. The centre of the ring is at a distance of d = R from the centre of the sphere. The gravitational attraction between the sphere and the ring is
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