Let A = i^Acosθ+j^Asinθ be any vector. Another vector B which is perpendicular to A can be expressed as

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i^Bcosθ-j^Bsinθ

i^Bsinθ-j^Bcosθ

i^Bcosθ+j^Bsinθ

i^Bsinθ+j^Bcosθ

answer is B.

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Detailed Solution

Dot product of two perpendicular vectors should be zero .∴B=i^Bsinθ-j^Bcosθ[∵(i^Acosθ+j^Asinθ)·(i^Bsinθ-j^Bcosθ)=0]

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