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Questions  

Let A =  i^Acosθ+j^Asinθ be any vector. Another vector B which is perpendicular to A can be expressed as

a
i^Bcosθ-j^Bsinθ
b
i^Bsinθ-j^Bcosθ
c
i^Bcosθ+j^Bsinθ
d
i^Bsinθ+j^Bcosθ

detailed solution

Correct option is B

Dot product of two perpendicular vectors should be zero .∴B=i^Bsinθ-j^Bcosθ[∵(i^Acosθ+j^Asinθ)·(i^Bsinθ-j^Bcosθ)=0]

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