Let K1 be the maximum kinetic energy of photoelectrons emitted by light of wavelengthλ1 and k2 corresponding to wavelength λ2. If λ1=2λ2 then :

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2K1 =K2

K1=2K2

K1>2K2

answer is C.

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Detailed Solution

given λ2 =λ12 frequency f2=2 f1 so if frequency becomes double kinetic energy becomes more than double

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