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Let $K_{1}$ be the maximum kinetic energy of photoelectrons emitted by light of wavelength $λ_{1}$ and $k_{2}$ corresponding to wavelength $λ_{2}$ . If $λ_{1} = 2 λ_{2}$ then :

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2K1 =K2

K1=2K2

K1>2K2

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detailed solution

Correct option is C

given λ2 =λ12 frequency f2=2 f1 so if frequency becomes double kinetic energy becomes more than double

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Let K1 be the maximum kinetic energy of photoelectrons emitted by light of wavelengthλ1 and k2 corresponding to wavelength λ2. If λ1=2λ2 then :

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Let $K_{1}$ be the maximum kinetic energy of photoelectrons emitted by light of wavelength $λ_{1}$ and $k_{2}$ corresponding to wavelength $λ_{2}$ . If $λ_{1} = 2 λ_{2}$ then :