Bohr Model of the Hydrogen atom.
Let the potential energy of Hydrogen atom in the ground state be zero. Then its orbital energy in the first excited state will be
Total energy in the ground state is
E = PE(U) + KE(K) = 0 + 13.6 eV = 13.6 eV
Energy required to shift to first excited state is
Total energy in the first excited state
= (13.6 + 10.2) eV = 23.8 eV
Talk to our academic expert!
Similar Questions
Find the potential energy of electron in first excited state if in the nth state, energy of electron in hydrogen atom is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
