Let the potential energy of Hydrogen atom in the ground state be zero. Then its orbital energy in the first excited state will be

Total energy in the ground state isE = PE(U) + KE(K) = 0 + 13.6 eV = 13.6 eV Energy required to shift to first excited state is E2−E1=ΔE=−13.622 − −13.6eV=10.2  eV∴Total energy in the first excited state  = (13.6 + 10.2) eV = 23.8 eV