Let the symbols E, m, I and G denote energy, mass, angular momentum and gravitational constant respectively. Then figure out the dimensions of the quantity El2m5G2.

[E]=ML2T−2,[m]=[M][l]=ML2T−1,[G]=M−1L3T−2∴El2m5G2=ML2T−2M2L4T−2M5M−2L6T−4=M0L0T0As angle has no dimensions, therefore El2m5G2 has the same dimensions as that of angle.