Download the app

Questions  

Let v1 be the frequency of series limit of Lyman series, v2 the frequency of the first line of Lyman series, and v3 the frequency of series limit of Balmer series. Then which of the following is correct?

a
v1−v2=v3
b
v2−v1=v3
c
v3=12v1+v2
d
v2+v1=v3

detailed solution

Correct option is A

Series limit means the shortest possible wavelength (maximum photon energy) and first line means the largest possible wavelength (minimum photon energy) in the series.v=C1n2−1m2                (where C is a constant)For series limit of Lyman series:n=1,m=∞ ⇒ v1=CFor first line of Lyman series:n=1,m=2 ⇒ v2=3C/4For series limit of Balmer series:n=2,m=∞ ⇒ v3=C/4Only option (a) is correct.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Determine the separation of the first line of the Balmer series (in ) in a spectrum of ordinary hydrogen and tritium (mass number 3). Take Rydberg's constants = 10967800 m-1.


phone icon
whats app icon