Let v1 be the frequency of series limit of Lyman series, v2 the frequency of the first line of Lyman series, and v3 the frequency of series limit of Balmer series. Then which of the following is correct?
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a
v1−v2=v3
b
v2−v1=v3
c
v3=12v1+v2
d
v2+v1=v3
answer is A.
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Detailed Solution
Series limit means the shortest possible wavelength (maximum photon energy) and first line means the largest possible wavelength (minimum photon energy) in the series.v=C1n2−1m2 (where C is a constant)For series limit of Lyman series:n=1,m=∞ ⇒ v1=CFor first line of Lyman series:n=1,m=2 ⇒ v2=3C/4For series limit of Balmer series:n=2,m=∞ ⇒ v3=C/4Only option (a) is correct.