Let $$V0$$ be the potential at the origin in an electric field E→$$=Exi^+Eyj^$$. The potential at the point (x$$,$$y) is

Correct option is 1V0−xEx−yEy

Questions

Let $V_{0}$ be the potential at the origin in an electric field $\vec{E} = E_{x} \hat{i} + E_{y} \hat{j} .$ The potential at the point $(x, y)$ is

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V0−xEx−yEy

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detailed solution

Correct option is A

Ex=−∂V∂x Ey=−∂V∂yIf y is constant (=0),∫V0VAdV=−∫0xExdxOr VA−V0=−Exx.Where x is constant (=x),∫VAVBdV=−∫0yEydyOr VB−VA=−Eydy .Adding, VB−V0=−xEx−yEyOr VB=V0−xEx−yEy .

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Let V0 be the potential at the origin in an electric field E→=Exi^+Eyj^. The potential at the point (x,y) is

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Let $V_{0}$ be the potential at the origin in an electric field $\vec{E} = E_{x} \hat{i} + E_{y} \hat{j} .$ The potential at the point $(x, y)$ is