Q.
The level of a liquid in a vessel kept constant at 50 cm. It has three identical horizontal tubes each of length 60 cm coming out at heights 5,10 and 15 cm respectively. If a single tube of the same radius as that of the three tubes can replace the three tubes when placed horizontally at the bottom of the vessel length of that tube is
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a
25 cm
b
40 cm
c
12.5 cm
d
50 cm
answer is A.
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Detailed Solution
πPr48ηl=πP1r48ηl1+πP2r48ηl2+πP3r48ηl3HL=H−h1l+H−h2l+H−h3l50L=4560+4060+3560⇒L=25cm