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The level of water in tank is 5 m high. A hole of area 1cm2 is made at the bottom of the tank. The rate of leakage of water from the hole is (g=10ms2)

a
10−3 m3s−1
b
10−4 m3s−1
c
10  m3s−1
d
10−2  m3s−1

detailed solution

Correct option is A

v=2gh Since volume flowing per second is Q=Av=A2gh=(1×10−4)×2×10×5 ⇒  Q=10−3 m3s−1

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