Questions
A lift of mass m is supported by a cable that can with stand a force of 3mg. Find the shortest distance in which the lift can be stopped when it is descending with a speed of
detailed solution
Correct option is D
Given T=m(g+a) ⇒3mg=m(g+a) ⇒a=2g V2−u2=2as 0−(g4)2=2(2g)×s⇒s=g64mTalk to our academic expert!
Similar Questions
Figure shows block A a motor C mounted on a with combined mass m and another block B of mass 2m. Block B is attached to shaft of motor with a light inextensible string. Motor is switched on at t =0 and string starts winding on its shaft and block B starts moving at acceleration a. If initial separation between blocks is l then find the time after which the two bodies will collide. The friction coefficient between blocks and ground is .
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