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Q.

A lift starting from rest with a constant upward acceleration moves 1.5 m in 004 s. If a person standingin the lift holds a packet of 2 kg by a string, then the tension in the string due to motion is  [UP CPMT 2013]

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a

5.89 N

b

57.1 N

c

67.1 N

d

None of these

answer is B.

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Detailed Solution

Given, u = 0, s = 1.5 m, t = 0.4 sFrom second equation of motion,   s=ut+12at2⇒  1.5=0+12a(0.4)2⇒  a=1.5×2(0.4)2=18.75 ms-2As the string is moving upwards with this acceleration∴T=m(g+a)=2(9.8+18.75)=57.1 N
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