Questions
A lift starting from rest with a constant upward acceleration moves 1.5 m in 004 s. If a person standing
in the lift holds a packet of 2 kg by a string, then the tension in the string due to motion is
[UP CPMT 2013]
detailed solution
Correct option is B
Given, u = 0, s = 1.5 m, t = 0.4 sFrom second equation of motion, s=ut+12at2⇒ 1.5=0+12a(0.4)2⇒ a=1.5×2(0.4)2=18.75 ms-2As the string is moving upwards with this acceleration∴T=m(g+a)=2(9.8+18.75)=57.1 NTalk to our academic expert!
Similar Questions
Two forces are acting on a rope lying on a smooth table as shown in figure.
Which of the following statement (s) is/are correct?
I. In moving from A to B, tension on string decreases from 2F to F.
II. Situation will becomes indeterminant, if we take it a massless string.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
