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Q.

A lift is tied with thick wires and the mass of the lift is one metric ton.  If the maximum acceleration of the lift is 1ms−2 and the maximum stress of the wire is 1.4×108Nm−2 . If g=10m/sec2 the minimum diameter of that wire is ----

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a

10m

b

10−1m

c

10−2m

d

None

answer is C.

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Detailed Solution

FA=m(g+a)πr21.4×108=100010+13.14r2r=5mm and D=10mm=10-2m
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