First slide

Potential energy

Question

A lifting machine, having an efficiency of 80% uses 2500 J of energy in lifting a 10 kg load over a certain height. If the load is now allowed to fall through that height freely, its velocity at the end of the fall will be (take acceleration due to gravity as 10 m/s2 )…….ms^-1

Moderate

A

10
B

15
C

20
D

25

Solution

$\frac{80}{100} x 2500 = \frac{10 v^{2}}{2} v = 20 m s^{- 1}$

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