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Q.

A light beam is incident on a denser medium whose  refractive index is 1.414 at an angle of incidence 45°.  Find the ratio of width of refracted beam in a medium  to the width of the incident beam in air.

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answer is 4.

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Detailed Solution

μ=1.414,     i=450sinisinr=μ12  = 1.414   sinrsin r=12  ⇒  r = 300sin450=ABAC,       cos300=CDACWidth in rarer medium AB=AC2  Width in denser medium CD=3AC2CDAB=3/21/2  =  32
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