Q.

A light bulb and an inductor coil are connected to an ac source through a key as shown in the figure below. The key is closed and after sometime an iron rod is inserted into the interior of the inductor. The glow of the light bulb

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a

increases

b

decreases

c

remains unchanged

d

will fluctuate

answer is B.

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Detailed Solution

As an iron rod is inserted, inductance of inductor will increase. Hence impedance z=R2+(ωL)2will increase, so from i=vzcurrent will decrease and from P=V02R2z2power of bulb will decrease.
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