First slide
Law of equipartition of energy
Question

A light container having a diatomic gas enclosed with in is moving with velocity v. Mass of the gas is M and number of moles is n. The kinetic energy of gas w.r.t. ground is

 

Moderate
Solution

The kinetic energy of gas w.r.t. centre of mass of the system  K.E. = 52nRT

Kinetic energy of gas w.r.t. ground = Kinetic energy of centre of mass w.r.t. ground + Kinetic energy of gas w.r.t. centre of mass.

K.E. = 12MV2+52nRT

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