Kinetic theory of ideal gases
A light container having a monoatomic ideal gas enclosed within is moving with speed v1. Its speed is suddenly reduced to v2. Find the resulting change in temperature. (Mass of each molecule of gas = m, k = Boltzmann constant).
Loss in kinetic energy of container is converted to random motion of molecules.
(Since monoatomic gas has three degrees of freedom).
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Two identical containers A and B have frictionless pistons. They contain the same volume of an ideal gas at the same temperature. The mass of the gas in A is mA and that in B is mB. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The change in the pressure in A and B, respectively, is p and 1.5 p. Then
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