Light described at a place by equation E=200vmsin2×1015s−1t+sin10×1015s−1t falls on metal surface having work function 2 eV, the maximum kinetic energy of photoelectrons?
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a
8 eV
b
10 eV
c
4.59 eV
d
3.27 eV
answer is C.
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Detailed Solution
Larger frequency =v=10×10152π=5×1015πS−1KEmax=hv−ω0⇒4.14×10−155×1015π−2eV⇒(6.59−2)eV=4.59eV