Questions
A light emitting diode (LED) has a voltage drop of 2 V across it and passes a current of 10 mA. When it operates with a 6 V battery through a limiting resistor R, the value of .R is
detailed solution
Correct option is A
The term LED is abbreviated as 'Light Emitting Diode'. It is forward biased p-n junction which emits spontaneous radiation. Current in the circuit= 10 mA = 10 x103 A and voltage in the circuit = 6 - 2= 4V From Ohm's law, V = IR∴R=VI=410×10−3=400 ΩTalk to our academic expert!
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An LED is constructed from a PN junction based on a certain semi-conducting material whose energy gap is 4 eV. Then the wavelength of the emitted light is
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