First slide

Photo Electric Effect

Question

Light of frequency $8 \times 10^{15}$ Hz is incident on a substance of photoelectric work function 6.125 eV. The maximum kinetic energy of the emitted photoelectrons is

Moderate

A

17 eV
B

22 eV
C

27 eV
D

37 eV

Solution

$\begin{array}{l} E = hv = 6 .6 \times 10^{- 34} \times 8 \times 10^{15} = 5 .28 \times 10^{- 18} J = 33 eV \\ By using E = W_{o} + K_{\max} \Rightarrow K_{\max} = E - W_{o} \\ = 33 - 6 .125 \approx 27 eV \end{array}$

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