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Q.

Light from a hydrogen discharge tube is incident on the cathode of a photoelectric cell the work function of the cathode surface is 4.2 eV. In order to reduce the photocurrent to zero the voltage of the anode relative to the cathode must be made

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a

- 4.2 V

b

- 9.4 V

c

-17.8 V

d

+9.4 V

answer is B.

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Detailed Solution

E=Wo+eVoFor  hydrogen  atom ,E=+13.6eV∴+13.6=4.2+eVo⇒Vo=13.6−4.2eVe=9.4VPotential  at  anode=−9.4V
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Light from a hydrogen discharge tube is incident on the cathode of a photoelectric cell the work function of the cathode surface is 4.2 eV. In order to reduce the photocurrent to zero the voltage of the anode relative to the cathode must be made