Light guidance in an optical fiber can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2. The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sinim.For two structures namely S1 with n1=45/4 and n2=3/2, and S2 with n1=8/5 and n2=7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is (are)If two structures of same cross-sectional area, but different numerical apertures NA1 and NA2NA2
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a
NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive index 16315
b
NA of S1 immersed in liquid of refractive index 615 is the same as that of S2 immersed in water
c
NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive index 415
d
NA of S1 placed in air is the same as that of S2 placed in water