First slide

Diffraction of light-Wave Optics

Question

A light has amplitude A and angle between analyser and polariser is 60°. Light is reflected by analyser has amplitude

Easy

A

$A \sqrt{2}$
B

$A / \sqrt{2}$
C

$\sqrt{3} A / 2$
D

$A / 2$

Solution

The amplitude will be $Acos 60^{\circ} = A / 2$

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