A light ray from air is incident (as$$ shown in $$figure) at one end of a glass fiber (refractive$$ index μ $$=$$ $$1.5) making an incidence angle of $$60$$° on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length $$1$$ km

Question

A light ray from air is incident (as$$ shown in $$figure) at one end of a glass fiber (refractive$$ index μ $$=$$ $$1.5) making an incidence angle of $$60$$° on the lateral surface, so that it undergoes a total internal reflection.  How much time would it take to traverse the straight fiber of length $$1$$ km

Infinity Learn · Accepted Answer

When total internal reflection just takes place from lateral surface $$i=C$$ i.e., $$60$$∘$$=CTime$$ taken by light to traverse some distance in a medium $$t=$$μ$$xc=23$$×$$1033$$×$$108=3.85$$ μ$$sec$$

A light ray from air is incident (as shown in figure) at one end of a glass fiber (refractive index $μ$ = 1.5) making an incidence angle of 60° on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length 1 km

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A light ray from air is incident (as shown in figure) at one end of a glass fiber (refractive index μ = 1.5) making an incidence angle of 60° on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length 1 km

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A light ray from air is incident (as shown in figure) at one end of a glass fiber (refractive index $μ$ = 1.5) making an incidence angle of 60° on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length 1 km