A light ray from air is incident (as$$ shown in $$figure) at one end of a glass fiber (refractive$$ index m $$=$$ $$1.5) making an incidence angle of $$60o$$ on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length $$1$$ $$km(nearly)$$

Question

Infinity Learn · Accepted Answer

⇒$$sin60o=1x$$⇒$$1x=32dist$$ travelled by ray of $$lightd=x1$$ x $$1$$ $$km=23$$ x $$103$$ m ⇒$$t=dv=dC0/$$μ$$=d$$μ$$C0$$⇒$$t=23$$ x $$103$$ x $$323$$ x $$108=5.77$$ μs

A light ray from air is incident (as shown in figure) at one end of a glass fiber (refractive index m = 1.5) making an incidence angle of 60^o on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length 1 km(nearly)

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A light ray from air is incident (as shown in figure) at one end of a glass fiber (refractive index m = 1.5) making an incidence angle of 60o on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length 1 km(nearly)

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A light ray from air is incident (as shown in figure) at one end of a glass fiber (refractive index m = 1.5) making an incidence angle of 60^o on the lateral surface, so that it undergoes a total internal reflection. How much time would it take to traverse the straight fiber of length 1 km(nearly)