Questions
A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34°. If the shaded half of the prism is knocked off, the ray will
a
Suffer a deviation of 34°
b
Suffer a deviation of 68°
c
Suffer a deviation of 17°
d
Not come out of the prism
detailed solution
Correct option is C
By formula δ=(n−1)A⇒34=(n−1)A and in the second position δ′=(n−1)A2∴34δ′=(n−1)A(n−1)A2 or δ′=342=17∘Talk to our academic expert!
Similar Questions
Angle of deviation by a prism (refractive index = and supposing the angle of prism A to be small) can be given by
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