Questions
A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34°. If the shaded half of the prism is knocked off, the ray will
detailed solution
Correct option is C
By formula δ=n−1A⇒34=n−1A and in the second position δ'=n−1A2∴34δ'=n−1An−1A2 or δ'=342=17oTalk to our academic expert!
Similar Questions
ABC is an isosceles right angled triangle with the angle BAC 90o. A ray of light parallel to the base BC strikes the face AB. The refracted ray in the prism strikes the base BC. If the refractive index of the material of the prism is , find the total angle of deviation of the final emergent ray
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