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Q.

A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34°. If the shaded half of the prism is knocked off, the ray will

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a

Suffer a deviation of 34°

b

Suffer a deviation of 68°

c

Suffer a deviation of 17°

d

Not come out of the prism

answer is C.

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Detailed Solution

By  formula  δ=n−1A⇒34=n−1A  and  in the  second  position  δ'=n−1A2∴34δ'=n−1An−1A2  or  δ'=342=17o
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