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Light reaches at a point P via two different paths(i) Direct (ii) After reflection from a plane mirror. Path difference between the two path is $\frac{5 λ}{2}$ , then the intensity at point P in terms of intensity due to source of light (I) is

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detailed solution

Correct option is D

Optical path difference when light directly comes = 5λ2Path difference when light comes after reflection =5λ2+λ2=6λ2⇒even multiple of λ2 so phase difference is 0 or 2πIR=4Icos2ϕ2, IR=4I

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