Download the app

Questions  

A light rod of length l has two masses m1 and m2 attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is

a
(m1+m2)l2
b
m1m2l2
c
m1m2m1+m2l2
d
m1+m2m1m2l2

detailed solution

Correct option is C

r1 = m2lm1+m2,    r2  = m1lm1+m2Icm = m1r21+m2r22 = m1m2m1+m2l2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Three point masses, each of m, are placed at the corners of an equilateral triangle of side l. Then the moment of inertia of this system about an axis along one side of the triangle is


phone icon
whats app icon