First slide
Moment of intertia
Question

A light rod of length l has two masses m1 and m2 attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is

Moderate
Solution

r1 = m2lm1+m2,    r2  = m1lm1+m2

Icm = m1r21+m2r22 = m1m2m1+m2l2

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