Questions
A light rod of length l has two masses and attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is
detailed solution
Correct option is A
Here, l1+l2=lCentre of mass of the system,l1=m1×0+m2×lm1+m2=m2lm1+m2l2=l-l1=m1lm1+m2Required moment of inertia of the systemI=m1l12+m2l22=m1m22+m2m12l2m1+m22=m1m2m1+m2l2m1+m22=m1m2m1+m2l2Talk to our academic expert!
Similar Questions
Three point masses, each of m, are placed at the corners of an equilateral triangle of side l. Then the moment of inertia of this system about an axis along one side of the triangle is
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