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Q.

A light rod is pivoted at one end so that it can swing freely as a pendulum. Two masses 2m and m are attached to it at distances b and 3b respectively from the pivot. The rod is held horizontal and then released the angular acceleration at the instant it is released is

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a

3mg4b

b

gb

c

5g11b

d

11g5b

answer is C.

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Detailed Solution

mass 2m at a distance b and mass m at a distance 3b form the support. When they are released from the horizontal position the torque acting due to gravitational force  about the pivot is 2mgb+ mg 3b = 5mgbthen 5mgb= Iα  here  I =2mb2+m3b2 = 11mb211mb2 α =5mgb α =5g11b
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