First slide

Work done by Diff type of forces

Question

A light spring of length l and spring constant K is placed vertically on the table. A small ball of mass m is released on it. Height from the surface of the table at which the ball will have maximum velocity

Moderate

A

l
B

$l - \frac{2 mg}{K}$
C

Greater than l
D

$l - \frac{mg}{K}$

Solution

Acceleration a = mg - k $∆$ x
Velocity will be maximum when a = 0
$∴ Δx = \frac{mg}{k}$
So height h = $l - \frac{mg}{K}$

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