Work done by Diff type of forces

Question

A light spring of length *l* and spring constant K is placed vertically on the table. A small ball of mass m is released on it. Height from the surface of the table at which the ball will have maximum velocity

Moderate

Solution

Acceleration a = mg - k$\u2206$x

Velocity will be maximum when a = 0

$\therefore \mathrm{\Delta x}=\frac{\mathrm{mg}}{\mathrm{k}}$

So height h = $\mathrm{l}-\frac{\mathrm{mg}}{\mathrm{K}}$

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