A light straight slider 1 m long can slide over two straight long parallel rails, vertically kept. when a uniform magnetic field of 0.6 T is applied perpendicular to the plane of rails, the slider is found moving with a constant velocity.
At this instant power dissipated in rails and slider due to their resistance is 1.96 W. If slider has a mass of 0.2kg, then the terminal velocity of the slider is ________.
Let v be the terminal velocity of the slider then, emf developed =e=Blv
When slider achieve terminal velocity, net downward force on slider is zero.
Or magnetic force = gravitational force
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Similar Questions
The diagram shows a circuit having a coil of resistance and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.
At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.
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