Questions
A light string of 70 cm has its two ends tied at the same level 50 cm apart. A force of 100 N is applied at a distance of 30 cm from P. The tension in part PR is
detailed solution
Correct option is D
Here T1 cos (90-θ)+T2 cos θ = 100And T1 cos θ = T2 cos (90-θ)Solving, T1 = 80 NTalk to our academic expert!
Similar Questions
A uniform sphere of weight W and radius 3 m is being held by a string of length 2m.attached to a frictionless wall as shown in the t figure. The tension in the string will be:
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