Q.

A light string of 70 cm has its two ends tied at the same level 50 cm apart. A force of 100 N is applied at a distance of 30 cm from P. The tension in part PR is

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a

18 N

b

8 N

c

0 N

d

80 N

answer is D.

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Detailed Solution

Here T1 cos (90-θ)+T2 cos θ = 100And T1 cos θ = T2 cos (90-θ)Solving, T1 = 80 N
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A light string of 70 cm has its two ends tied at the same level 50 cm apart. A force of 100 N is applied at a distance of 30 cm from P. The tension in part PR is