Q.
A light string of 70 cm has its two ends tied at the same level 50 cm apart. A force of 100 N is applied at a distance of 30 cm from P. The tension in part PR is
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a
18 N
b
8 N
c
0 N
d
80 N
answer is D.
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Detailed Solution
Here T1 cos (90-θ)+T2 cos θ = 100And T1 cos θ = T2 cos (90-θ)Solving, T1 = 80 N
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