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A light string of length 20cm is carrying a bob of mass 100 gm. It is pulled through an angle $60^{0}$ and released. Its maximum velocity is, $(g = 10 m^{- 2})$

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1ms−1

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detailed solution

Correct option is C

12mV2=mgℓ(1−cosθ) u=2gl(1−Cosθ)=2×10×20×10−2(1−cos600)V=1.4ms−1

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A light string of length 20cm is carrying a bob of mass 100 gm. It is pulled through an angle 600 and released. Its maximum velocity is, (g=10m−2)

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A light string of length 20cm is carrying a bob of mass 100 gm. It is pulled through an angle $60^{0}$ and released. Its maximum velocity is, $(g = 10 m^{- 2})$