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A light string of length 10cm is carrying a bob of mass 100 gm. It is pulled through an angle 60⁰and released. Its maximum velocity is, $(g = 10 m s^{- 2})$

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detailed solution

Correct option is C

12mV2=mgℓ(1−cosθ) V=2gℓ(1−cosθ) =2×10×10×10−2(1−cos60) = 1 m/s

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A light string of length 10cm is carrying a bob of mass 100 gm. It is pulled through an angle 600 and released. Its maximum velocity is, (g=10ms−2)

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A light string of length 10cm is carrying a bob of mass 100 gm. It is pulled through an angle 60⁰and released. Its maximum velocity is, $(g = 10 m s^{- 2})$