Application of Newtons laws

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Question

A light string passes over a frictionless pulley. To one of its ends a mass of 6 kg is attached. To its other end a mass of 10 kg is attached. The tension (in newton) in the thread will be $[Take g = 9.8 m / s^{2}]$

Easy

Solution

$T = \frac{2 m_{1} m_{2}}{m_{1} + m_{2}} g = \frac{2 \times 10 \times 6}{10 + 6} \times 9.8 = 73.5 N$

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