First slide

Photoelectric effect and study of photoelectric effect

Question

Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, successively illuminates a metal of work function 0.5 eV. If the maximum kinetic energies of emitted electron is K₁ and K₂respectively. The ratio $\frac{K_{2}}{K_{1}}$ is __________

Moderate

Solution

$\begin{array}{l} By using E = W_{0} + K_{max} \Rightarrow K_{max} = E - W_{0} \\ Hence, K_{1} = 1 - 0.5 = 0.5 \\ and K_{2} = 2.5 - 0.5 = 2 \Rightarrow \frac{K_{1}}{K_{2}} = \frac{1}{4} \end{array}$

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