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Q.

Light wave enters from medium 1 to medium 2. Its velocity in 2nd medium is double from 1st. For total internal reflection the angle of incidence must be greater than

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a

30°

b

60°

c

45°

d

90°

answer is A.

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Detailed Solution

μ2μ1=v1v2=12⇒μ1μ2=2μ1>μ2  For total internal reflection 2μ1=1sin⁡C⇒μ1μ2 =1sin⁡C⇒2=1sin⁡C⇒C=30∘ So, for total Internal reflection angle of incidence must be greater than 30°.
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Light wave enters from medium 1 to medium 2. Its velocity in 2nd medium is double from 1st. For total internal reflection the angle of incidence must be greater than