Light wave enters from medium 1 to medium 2. Its velocity in 2nd medium is double from 1st. For total internal reflection the angle of incidence must be greater than
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a
30°
b
60°
c
45°
d
90°
answer is A.
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Detailed Solution
μ2μ1=v1v2=12⇒μ1μ2=2μ1>μ2 For total internal reflection 2μ1=1sinC⇒μ1μ2 =1sinC⇒2=1sinC⇒C=30∘ So, for total Internal reflection angle of incidence must be greater than 30°.
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Light wave enters from medium 1 to medium 2. Its velocity in 2nd medium is double from 1st. For total internal reflection the angle of incidence must be greater than