First slide

Total internal reflection - Ray optics and optical instruments

Question

Light wave enters from medium 1 to medium 2. Its velocity in 2nd medium is double from 1st. For total internal reflection the angle of incidence must be greater than

Moderate

A

30°
B

60°
C

45°
D

90°

Solution

$\frac{μ_{2}}{μ_{1}} = \frac{v_{1}}{v_{2}} = \frac{1}{2} \Rightarrow \frac{μ_{1}}{μ_{2}} = 2 (μ_{1} > μ_{2}) {For total internal reflection}_{2} μ_{1} = \frac{1}{\sin C} \Rightarrow \frac{μ_{1}}{μ_{2}} = \frac{1}{\sin C} \Rightarrow 2 = \frac{1}{\sin C} \Rightarrow C = 30^{\circ}$
So, for total Internal reflection angle of incidence must be greater than 30°.

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