First slide

Diffraction of light-Wave Optics

Question

A light wave is incident normally over a slit of width $24 \times 10^{- 5} cm$ . The angular position of second dark fringe from the central maxima is 30°. What is the wavelength of light

Easy

A

$6000 Å$
B

$5000 Å$
C

$3000 Å$
D

$1500 Å$

Solution

For second dark fringe $dsin θ = 2 λ$
$\Rightarrow 24 \times 10^{- 5} \times 10^{- 2} \times \sin 30 = 2 λ \Rightarrow λ = 6 \times 10^{- 7} m = 6000 A$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App