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Q.

A light wave is incident normally over a slit of width 24×10−5cm. The angular position of second dark fringe from the central maxima is 30°. What is the wavelength of light

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a

6000Å

b

5000Å

c

3000Å

d

1500Å

answer is A.

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Detailed Solution

For second dark fringe dsin⁡θ=2λ⇒24×10−5×10−2×sin⁡30=2λ ⇒λ=6×10−7m=6000A
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