First slide

Diffraction

Question

A light wave is incident normally over a slit of width $24 \times 10^{- 5} cm .$ The angular position of second dark fringe from the central maxima is 30⁰. What is the wavelength of light?

Moderate

A

$6000 Å$
B

$5000 Å$
C

$3000 Å$
D

$1500 Å$

Solution

For second dark fringe d $\sin θ = 2 λ$
$\Rightarrow 24 \times 10^{- 5} \times 10^{- 2} \times \sin 30^{\circ} = 2 λ$
$\Rightarrow λ = 6 \times 10^{- 7} m = 6000 Å$

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