A light of wavelength 5890 Å falls normally on a thin air film. The minimum thickness of the film such that the film appears dark in reflected light
2.945×10−7m
3.945×10−7m
4.95×10−7m
1.945×10−7m
If thin film appears dark
2μtcosr=nλ for normal incidence r=0∘ ⇒2μt=nλ⇒t=nλ2μ ⇒tmin=λ2μ=5890×10−102×1=2.945×10−7m