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Questions  

A light of wavelength 5890 Å falls normally on a thin air film. The minimum thickness of the film such that the film appears dark in reflected light    

a
2.945×10−7m
b
3.945×10−7m
c
4.95×10−7m
d
1.945×10−7m

detailed solution

Correct option is A

If thin film appears dark 2μtcos⁡r=nλ for normal incidence r=0∘ ⇒2μt=nλ⇒t=nλ2μ ⇒tmin=λ2μ=5890×10−102×1=2.945×10−7m

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