Questions
A light of wavelength 5890 Å falls normally on a thin air film. The minimum thickness of the film such that the film appears dark in reflected light
detailed solution
Correct option is A
If thin film appears dark 2μtcosr=nλ for normal incidence r=0∘ ⇒2μt=nλ⇒t=nλ2μ ⇒tmin=λ2μ=5890×10−102×1=2.945×10−7mTalk to our academic expert!
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