A light of wavelength 5890 Å falls normally on a thin air film. The minimum thickness of the film such that the film appears dark in reflected light is
2.945×10−7m
3.945×10−7m
4.95×10−7m
1.945×10−7m
If thin film appears dark
2μt cos r=nλ for normal incidence r=0∘
⇒2μt=nλ ⇒ t=nλ2μ
⇒tmin=λ2μ=5890×10−102×1
=2.945×10−7m.