Light of wavelength 6328 Å is incident normally on a slit having a width of 0.2 mm. the distance of the screen from the slit is 0.9 m. The angular width of the central maximum is

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0.09 degree

0.72 degree

0.18 degree

0.36 degree

answer is D.

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Detailed Solution

β=λDdSo, angular with, 2θ is2θ=2βD=2λdθ=6328×10−100.2×10−3⇒θ=3164×10−6 radian ⇒θ=3164×10−6×180π degree ⇒θ=0.18 degree ⇒2θ=0.36 degree.

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