Diffraction

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Question

Light of wavelength 5000A⁰ is incident on a slit. The first minimum of the diffraction pattern is observed to lie at a distance of 5 mm from the central maximum on a screen placed at a distance of 3 m from the slit. Then the width of the slit is

Easy

Solution

Minimum condition for diffraction is
$d\frac{Y}{D} = n\lambda ,\,d\frac{{5 \times {{10}^{ - 3}}}}{3} = 1 \times 5000 \times {10^{ - 10}}\$
$d = 3 \times {10^{ - 4}}m = 0.03cm\$

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