First slide

Diffraction of light-Wave Optics

Question

The light of wavelength 6328 Å is incident on a slit of width 0.2 mm perpendicularly, the angular width of central maxima will be

Moderate

A

0.36°
B

$0 {.18}^{\circ}$
C

$0 {.72}^{\circ}$
D

$0 {.09}^{\circ}$

Solution

The angular half width of the central maxima is given by $\sin θ = \frac{λ}{a} \Rightarrow θ = \frac{6328 \times 10^{- 10}}{0 .2 \times 10^{- 3}} rad$
$= \frac{6328 \times 10^{- 10} \times 80}{0 .2 \times 10^{- 3} \times π} degree = 0 {.18}^{\circ}$
$Total width of central maxima = 2 θ = 0 {.36}^{\circ}$

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