First slide

Diffraction

Question

The light of wavelength $6328 Å$ is incident on a slit of width 0.2 mm perpendicularly, the angular width of central maxima will be

Easy

A

0.36⁰
B

0.18⁰
C

0.72⁰
D

0.09⁰

Solution

The angular half width of the central maxima is given by
$θ = \frac{λ}{a} \Rightarrow θ = \frac{6328 \times 10^{- 10}}{0 .2 \times 10^{- 3}} rad$
$= \frac{6328 \times 10^{- 10} \times 80}{0 .2 \times 10^{- 3} \times π} = 0 {.18}^{\circ}$
Total width of central maxima $= 2 θ = {0.36}^{\circ}$

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